Question

Dinitrogen and dihydrogen react with each other to produce ammonia according to the given chemical equation: N₂ (g) + H₂ (g) → 2NH₃ (g) Calculate the mass of ammonia produced if 2.00 × 10³ g dinitrogen reacts with 1.00 ×10³ g of hydrogen.

Answer 1

i) Balancing the given chemical equation,

 

From this equation, 1 mole (28 g) of dinitrogen reacts with 3 moles (6 g) of dihydrogen to give 2 moles (34 g) of ammonia.

So, 2.00 × 103g of dinitrogen will react with dihydrogen i.e.,2.00 × 103g of dinitrogen will react with 428.6 g of dihydrogen.

It is given that,

Amount of dihydrogen = 1.00 × 103g

Hence, N2 is the limiting reagent.

28 g of N2 produces 34 g of NH3.

Hence, mass of ammonia produced by 2000 g of N2=  of NH3  

                                                                                   =2428.57 g