Diogonals of rhombus is 16 and 30 find perimeter
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Answer:
in a rhombus
diagonals bisect each other
so half of them are
8 and 15
in a rhombus diagonals bisect at 90
so side of rhombus is hypotenuse
by pythagoras
(side) square = 8 square + 15 square
side ) square = 64 + 225 = 289 = 17 square
side = 17
perimeter = 4 x side = 4 x 17 = 68
Step-by-step explanation:
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