Directions IQ. Nos. (1)-(viDl Consider the figure of a rectangular park having length
40 m and width 30 m as shown below. Based on given information in each part, fill
blanks.
1 m
Path to be cemented
Grass
30 m
1.5 m
Rectangular flower beds
2 m
40 m
(1) Total length of the fence surrounding the park, will be
i) The land occupied by the park, is
m.
i) Area of path to be cemented =
m-
-) Area of the park left after cementing the path = _ m
m
=
m
=
Answers
Answer:
Step-by-step explanation:
1
i) Land occupies by the park is 40*30=1200m²
ii) Area of the path to be cemented if 1m is the width of the path
=(40*1)+(29*1)+(39*1)+(28*1)
=40+29+39+28
=136m²
iii) Area of the park left after cementing the path= Area of the park- area of the path
required=1200-136
=1064m²
Total length of the fence is 140m
Total land occupied by park is 1200m²
Area of path to be cemented is 136m²
Area of park left after cementing is 1064m²
• length of fence = perimeter
• perimeter = 2(L+B)
= 2(40+30)
= 2(70)
= 140m
• Total area of park = LxB
= 40×30
= 1200 m²
• Area of path to be cemented with width 1 m = 40×1+30×1+40×1+30×1-4
= 40 + 30 + 40 + 30 - 4
= 136 m²
• Area of park left after cementing = 1200-136=1064m²