Math, asked by nalingadroo31, 10 months ago

Directions IQ. Nos. (1)-(viDl Consider the figure of a rectangular park having length
40 m and width 30 m as shown below. Based on given information in each part, fill
blanks.
1 m
Path to be cemented
Grass
30 m
1.5 m
Rectangular flower beds
2 m
40 m
(1) Total length of the fence surrounding the park, will be
i) The land occupied by the park, is
m.
i) Area of path to be cemented =
m-
-) Area of the park left after cementing the path = _ m
m
=
m
=​

Answers

Answered by nainabansal207
2

Answer:

Step-by-step explanation:

1

i) Land occupies by the park is 40*30=1200m²

ii) Area of the path to be cemented if 1m is the width of the path

=(40*1)+(29*1)+(39*1)+(28*1)

=40+29+39+28

=136m²

iii) Area of the park left after cementing the path= Area of the park- area of the path

required=1200-136

=1064m²

Answered by AnkitaSahni
2

Total length of the fence is 140m

Total land occupied by park is 1200m²

Area of path to be cemented is 136m²

Area of park left after cementing is 1064m²

• length of fence = perimeter

• perimeter = 2(L+B)

= 2(40+30)

= 2(70)

= 140m

• Total area of park = LxB

= 40×30

= 1200 m²

• Area of path to be cemented with width 1 m = 40×1+30×1+40×1+30×1-4

= 40 + 30 + 40 + 30 - 4

= 136 m²

• Area of park left after cementing = 1200-136=1064m²

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