Question

Directions (Q.16 & Q.17) : A, B and C are playing a game. When they start, they have 46 points between the 3 of them. They play 3 games. A wins the first, the second and B the third game. When A wins, he gets 3 points from B and 3 points from C. When B wins, his points double and he gets some of these points from A and some from C. When C wins, he gets 2 points from A and 4 points from B. After the 3 games, all three of them have the same points with each of them that they had started with How many points did B start with ? (1) 12 (2) 16 (4) cannot be determined (3) 14 When B wins, how many points does he get from C ?(1) 5 (2) 3 (3) either 3 or 4 (4)4 with reason??​

Answer 1

Answer:

Q16- (3)14

Q17- (2)3

Explanation:

Initial. A B C

Round 1. A+6 B-3 C-3

Round 2. A+6-2 B-3-4 C-3+4+2

Round 3. A+4-x 2(B-7) C-3-y

Let's assume that in round 3 A gave x points to B and C gave y points to B.

It is given that at the end, each of them had the same number of points that they had started with. So-

A = A+4-x

B = 2(B-7)

C = C-3-y

From the above three equations, B=14, x=4 and y=3.

So B had started with 14 points and when B won, he got 3 points from C.