Question

The first term of an A.P.is 6 and the common difference is 2, then determine the 15th term.​

Answer 1

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Answer 2

$\large{\underline{\underline{\mathfrak{\sf{\red{Answer-}}}}}}$

15th term of an AP is 34.

$\large{\underline{\underline{\mathfrak{\sf{\red{Explanation-}}}}}}$

Given :

• First term ( a ) = 6
• Common difference ( d ) = 2

To find :

• Fifteenth term of AP ( $\sf{a_{15}}$ )

Solution :

We know that,

$\sf{a_n=a+(n-1)d}$

Putting the given values, for finding $\bold{sf{a_15}}$

$\implies$ $\sf{a_{15}=a+(15-1)d}$

$\implies$ $\sf{a_{15}=a+14d}$

$\implies$ $\sf{a_{15}=6+14(2)}$

$\implies$ $\sf{a_{15}=6+28}$

$\implies$ $\sf{a_{15}=34}$

Therefore, 15th term of an AP is 34.