Question

Discrepancy of d/dx (8x²+4x+3x³-4x⁵+1) =?​

Answer 1

Answer:

$Y = 8x {}^{2} + 4x + 3x {}^{3} - 4x {}^{5} + 1$

Differnatatiating with respect to X

$\frac{dy}{dx} = \frac{d(8x {}^{2} + 4x + {3x}^{3} - {4x}^{5} + 1}{dx}$

$\frac{dy}{dx} = \frac{d(8x {}^{2} ) }{dx} + \frac{d(4x)}{dx} + \frac{d3x {}^{3} }{dx} - \frac{d(4 {x}^{5}) }{dx} + \frac{d(1)}{dx}$

$\frac{dy}{dx} = (2 \times 8x) +( 4 \times 1) + (3 \times 3 {x}^{2}) -( 5 \times 4 {x}^{4} ) + (1 \times 0)$

$\frac{dy}{dx} = 16x + 4 + 9x {}^{2} - 20x {}^{4} + 0$

$\frac{dy}{dx} = - 20x {}^{4} + 9 {x}^{2} + 16x + 4$

$\frac{dy}{dx} = - (20 {x}^{4} - 9x {}^{2} - 16x - 4)$

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