Discriminate of the quadratic equations (x-a) (x-b) =c square is
Answers
Answered by
5
Answer:
Note;
If we consider a quadratic equation;
say: Ax^2 + Bx + C = 0
Then, the discriminant is given by;
D = B^2 - 4•A•C
Here, the given equation is;
=> (x - a)(x - b) = c
=> x^2 - bx - ax + ab = c
=> x^2 - (a + b)x + ab - c = 0
Clearly, here we have;
A = 1
B = - (a + b)
C = ab - c
Now, putting these values, we get;
=> D = B^2 - 4•A•C
=> D = { - (a + b)}^2 - 4•1•(ab - c)
=> D = a^2 + b^2 + 2ab - 4ab + 4c
=> D = a^2 + b^2 - 2ab + 4c
Thus, the value of discriminant of the given equation is:
a^2 + b^2 - 2ab + 4c
or
(a-b)^2 + 4c
Answered by
1
Answer:
(a-b) square + 4 c square
Step-by-step explanation:
option b
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