Question

Discriminate of the quadratic equations (x-a) (x-b) =c square is

Answer 1

Answer:

Note;

If we consider a quadratic equation;

say: Ax^2 + Bx + C = 0

Then, the discriminant is given by;

D = B^2 - 4•A•C

Here, the given equation is;

=> (x - a)(x - b) = c

=> x^2 - bx - ax + ab = c

=> x^2 - (a + b)x + ab - c = 0

Clearly, here we have;

A = 1

B = - (a + b)

C = ab - c

Now, putting these values, we get;

=> D = B^2 - 4•A•C

=> D = { - (a + b)}^2 - 4•1•(ab - c)

=> D = a^2 + b^2 + 2ab - 4ab + 4c

=> D = a^2 + b^2 - 2ab + 4c

Thus, the value of discriminant of the given equation is:

a^2 + b^2 - 2ab + 4c

or

(a-b)^2 + 4c

Answer 2

Answer:

(a-b) square + 4 c square

Step-by-step explanation:

option b