Physics, asked by Nomfundo2536, 8 months ago

Discuse the shortcoming of the classical mechanics

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Answered by Anonymous
2

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☆ When the velocity of the particle becomes nearer to the velocity of light, measurement of mass of the particle is found to be increased, time of the frame is found to decrease is found to decrease. These cannot be explained on the basis of classical physics.

☆ Classical physics is found to be inconsistent with Maxwell’s electrodynamics.

☆ Classical physics fails to account for wave like nature of the microscopic particles, blackbody radiation anomalous Zeeman effect fine structures in atomic spectra and photoelectric effect.

☆ Classical physics fails to explain the motion of heavenly bodies in strong gravitational fields e.g. motion of mercury at its perihelion and also it cannot explain bending of light in vicinity of massive gravitational bodies, gravitational lensing etc.

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Answered by SUBRATA4322
0

Answer:

A uniform metre scale has two weights of 10 gf and 8 gf suspended at the 10 cm and 80 cm marks respectively. If the metre scale itself weights 50 gf, find where must the weight be, so that the metre scale stays balanced?

December 30, 2019Archa Tawari

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ANSWER

Let the meter scales is balanced at X cm mark on the scale.

At the balancing condition, Anticlock wise moment must be equal to clock wise moment.

Clockwise moment, about the balancing point is

= moment by 80 gf

=80gf×(80−X)cm

=6400gfcm−80Xgfcm.....(1)

Anticlock wise moment about the balancing point is

= moment by 10 gf + moment by 50 gf

=10gf×(X−10)+50gf×(X−50)

=10Xgfc,−100gfcm+50Xgfcm−2500gfcm.....(2)

At the balancing condition, Clock wise at equilibrium = Anti clock wise moments.

6400−80X=100X−100+50X−2500

6400+2600=140X⇒140X=8000

⇒X=1408000=64.28

Scale is balanced at 64.28 cm from the beginning.

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