Question

Discuss sp2

hybridization in BCl3 molecule. Write its orbital structure.
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Answer 1

Answer:

The hybridization of BCl3 now occurs where one 2s and two 2p orbitals of boron will take part in the process to form three half-filled sp2 hybrid orbitals. ... Three σsp-p bonds are formed between boron's half-filled sp2 hybrid orbitals and three chlorine atoms.

Answer 2

▪️The type of hybridization that occurs in BCl3 is sp2 hybridization.

▪️In BCl3 molecule, boron will be the central atom which contains three bonded atoms but no lone pair of electrons. Its steric number is also said to be 3.

➡️Name of the Molecule: Boron Trichloride

➡️Molecular Formula : BCl3

➡️Hybridization Type: sp²

➡️Bond Angle : 120degree

➡️Geometry : Trigonal Planar

▪️ Know More :

The hybridization of BCl3 now occurs where one 2s and two 2p orbitals of boron will take part in the process to form three half-filled sp2 hybrid orbitals. Each sp2 hybrid orbitals will contain unpaired electrons that will overlap with the unpaired electron in chlorine’s 3p orbital. Three σsp-p bonds are formed between boron’s half-filled sp2 hybrid orbitals and three chlorine atoms.

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