Chemistry, asked by jokerman9801, 1 year ago

Discuss the equilibrium of a sparingly soluble salt

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Answered by Thakurs109
4

hay mate

here is your answer

This equilibrium constant is called the solubility product constant, (Ksp) and is equal to the mathematical product of the ions each raised to the power of the coefficient of the ion in the dissociation equation.

The stoichiometry of the formula of the ionic compound dictates the form of the Ksp expression. For example the formula of calcium phosphate is Ca3(PO4)2. The dissociation equation and Ksp expression are shown below:

Ca3(PO4)2(s)⇄3Ca2+(aq)+2PO3−4(aq)

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