A truck of mass 5000kg is moveing with velocity 72km/h .lt is brought to rest in adistance of 10m by application of breaks .calculate the retarding force acting on the car
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m=5000kg
vi=72km/h=20m/s
vf=0
d=10m
a=?
F=?
2as=vf2-vi2
2a(10)=(0)-(20)2
a= 20m/s2
F=ma
F= (5000)(20)
F= 10,000
vi=72km/h=20m/s
vf=0
d=10m
a=?
F=?
2as=vf2-vi2
2a(10)=(0)-(20)2
a= 20m/s2
F=ma
F= (5000)(20)
F= 10,000
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