the line joining the point 2, - 1 and 5,-6 is bisect at P . If P lies o bomb the line 2x+4y+k=0 find the value of k
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hy dude
the value of k is 14
plz check the answer and tell me
the value of k is 14
plz check the answer and tell me
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yash510:
plz check answer and tell me
but the ans is 7
Answered by
5
OK
Time for the proper answer
Get ready.
soln___
= The point p is the mid point of the points 2,-1 and 5,-6
= So by the mid point formula
=> p(x,y)= p(2+5/2,-1-6/2)
=> p(x,y)= p(7/2,-7/2)
now,
since, the point 'p' lies on the line 2x+4y+k=0
therefore,the coordinates of p are solution of the equation
Hence, plotting the points on the equation we get,
=>2*7/2+4*(-7/2)+k=0
=> 7-14+k. =0
=> k. =7
Time for the proper answer
Get ready.
soln___
= The point p is the mid point of the points 2,-1 and 5,-6
= So by the mid point formula
=> p(x,y)= p(2+5/2,-1-6/2)
=> p(x,y)= p(7/2,-7/2)
now,
since, the point 'p' lies on the line 2x+4y+k=0
therefore,the coordinates of p are solution of the equation
Hence, plotting the points on the equation we get,
=>2*7/2+4*(-7/2)+k=0
=> 7-14+k. =0
=> k. =7
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