Math, asked by Fasvin7573, 1 year ago

A taxi charges in a city comprises of a fixed charge together with the charges for the distance covered. for a journey of 10 km the charge paid is rs. 75. and for a journey of 15 km the charge paid is rs.110 what will a person have to pay for travelling a distance of 25 km

Answers

Answered by Anonymous
1

Answer:

Let the fixed charge of taxi be Rs. x per km and the running charge be Rs y per km.

According to the question,

⟹ x + 10y = 75

⟹ x + 15y = 110

Subtracting equation (ii) from equation (i), we get

⟹ – 5y = – 35

⟹ y = 7

Putting y = 7 in equation (i), we get x = 5

∴ Total charges for travelling a distance of 25 km = x + 25y

= (5 + 25 × 7)

= (5 + 175)

= Rs. 180

Answered by Anonymous
6

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