Math, asked by sri1842004, 24 days ago

discuss the maxima and minima of f(x y)=x^3+y^3+3x^2-3y^2-8 ​

Answers

Answered by bipinbaghel2007
0

(xy)=x³+y³+3x²-3y²-8

(xy)=x³+3x²+y³-3y²-8

(xy)=3x⁵-2y-8

xy=3x⁵-2y-8

3x⁴-y-8

x⁴-y=8/3

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