Question

What is the value for the equation?​

Answer 1

Answer:

your solution is as follows

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Step-by-step explanation:

$given \: trigonometric \: expression \: is \\ \\ cos {}^{2} \frac{\pi}{8} + 4cos {}^{2} \frac{\pi}{4} - sec \frac{\pi}{3} + 5tan {}^{2} \frac{\pi}{3} + sin {}^{2} \frac{\pi}{8} \\ \\ = (sin {}^{2} \frac{\pi}{8} + cos {}^{2} \frac{\pi}{8} \: ) + 4cos {}^{2} \frac{\pi}{4} + 5tan {}^{2} \frac{\pi}{3} - sec \frac{\pi}{3} \\ \\ = 1 + 4 \times ( \frac{1}{ \sqrt{2} } \: ) {}^{2} + 5 \times ( \sqrt{3} \: ) {}^{2} - 2 \\ \\ = 1 + 4 \times \frac{1}{2} + (5 \times 3) - 2 \\ \\ = 1 + 2 + 15 - 2 \\ \\ = 1 + 15 \\ \\ = 16$