discuss the nature of roots (-x²+3x+1=0).
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- x² + 3x + 1 = 0
By removing the ( - ) symbol before x² , we can change the symbols
New polynomial :- x² - 3x - 1 = 0
a = 1 , b = - 3 , c = - 1
• D = b² - 4ac
= ( - 3 ) ² - 4 x 1 x - 1
= 9 + 4
= 13
Now
x = - b ± √ D / 2a ( D = b² - 4ac )
x = - ( - 3 ) ± √13 / 2 x 1
x = 3 ± √13 / 2
So , x = 3 + √13 / 2 or 3 - √13 / 2
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