Question

Discuss the nature of the solutions of the quadratic equation x^2−4x+4=0

Answer 1

Answer:

let ax²+bx+c= o

a= 1

b= -4

c=4

discriminant

️b²-4ac = (-4)²-4×1×4=0

Answer 2

Answer:

➡ x²-4x+4 = 0

✏ a = 1, b = -4, c = 4

Therefore, the discriminate

=> b²-4ac = (-4)² - 4.1.4

= 16 - 16

= 0

Hence, the two roots of the given quadratic equation are real and equal.

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⭐ Extra Information :-

➡ The two roots of the quadratic equation ax²+bx+c = 0 [ a ≠ 0 ]

I) real and equal if b²- 4ac = 0

II) real and unequal if b²- 4ac > 0

III) no real root if b² - 4ac < 0