Question

find the smallest number by which each of the following number must be multiply to obtain perfect cube of 243​

Answer 1

Answer:

1. 243

Prime factors of 243 = 3×3×3×3×3

Here 3 does not appear in 3's group.

3|243

3|81

3|27

3|9

3|3

|1

Therefore,243 must be multiplied by 3 to make it a perfect cube.