Question

Displacement x of a particle along a straight line at time T is given by x is equal to a 0 + at +at2 square the acceleration of the particle is

Answer 1

we know , v = dx/dt

a = dv/dt

x = ao + a1t + a2t2

v= dx/dt = 0 + a1 + 2a2t

a=dv/dt = d/dt (a1+2a2t)

=0+2a2

differntiation of constant is 0...

so accleration of particle = 2a2

Answer 2

Answer:

Explanation:this is the answer