Question

Displacement x=t^3-12t+10.The acceleration of particle when velocity is 0

Answer 1

ANSWER:

acceleration =12 m/s²

Explanation:

Differentiate displacement x with respect to t

So dV=d(x) /dt

dv=d(t³-12t+10)/dt

=3t²-12

3t²-12=0

t=2

Now again on differentiating this equation we get slope of acceleration

a=dV/dt

a=d(3t²-12)/dt

=6t

So we get a=6t. —(I)

Now put the value of time as 2 in the eq(i)

We get a=6×2

So acceleration at velocity =6t is 12 m/s²

Answer 2

Answer:

12

Explanation: