Question

Dissolving 120 g urea (moloar mass 60g/mol) in1000g water gave a solution of density 1.15g/ml .the molarity of the solution is
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Answer 1

Answer:

120 gram urea is taken molar mass is 60 gram Mall in thousand gram water give a solution of density = 1.1 5G gram by millimetre molarity of the solution is equals to 120 all divided by 1.1 5G e = 20 by 30 ji

Answer 2

Answer:

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Explanation:

Molarity is defined as the number of moles of solute dissolved in per litre of solution.

Molarity, M= n/v

n=number of moles of solute=mass/molar mass

V=volume of solution

mass of urea (NH 2CONH2 )=120g

Molar mass of urea= 60g/mol

Mass of water=1000g

Density of solution. ρ=1.15 g/mL

n=120/60=2mol

m ssolutio =m solut +msolvent

(∵ Law of conservation of mass)

ρ ssolutio ×Vsolution

no=120+1000 (using m=ρ.V)

1.15×V

solution

=1120

solution

=974mL=0.974L

thus M= n/v

= 2/0.974

=2.05M

Molarity of the solution is 2.05M

Hence, the correct option is C