Question

distance =20m;initial veĺocity=0;acceleration =20m/s²;time=?​

Answer 1

Answer:

s=20m

u=0

a=20m/s2

By using, s=ut+1/2at^2

$20= \frac{1}{2} \times 20 \times {t}^{2} \\ {t}^{2} = \frac{20 \times 2}{20} \\ {t}^{2} = 2 \\ t = \sqrt{2}$

=1.414sec.

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Answer 2

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Time(t)=1.4\:sec }}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Distance (s) = 20m

• Initial Velocity (u) = 0m/s

• Acceleration (a) = 20 m/s²

$\large\underline\pink{\sf To\:Find: }$

• Time (t) = ?

━━━━━━━━━━━━━━━━━━━━━━━━━━

We know ,

$\Large{\boxed{\sf s=ut+\frac{1}{2}at^2}}$

$\large\implies{\sf 20=0+\frac{1}{2}20×t^2 }$

$\large\implies{\sf 20=10×t^2 }$

$\large\implies{\sf t^2=2}$

$\large\implies{\sf t=\sqrt{2} }$

$\large\implies{\sf t=1.4\:sec }$

$\large\red{\boxed{\sf Time(t)=1.4\:sec }}$