Distance between A(x,y)and B(-4,7) is √41 find x and y, if A's ordinate is thrice of it's abscissa
Answers
Answered by
24
y=3x(given)
:::>distance=root((x+4)^2+(3x-7)^2)=root (41)
squaring both sides
:::>10x^2-34x+65=41
:::>10x^2-34x+24=0 ||||| on solving we get x=1,(12/5)
:::>for x=1 y=3
and for x=12/5 , y=36/5
thus the solutions are (1,3) and (12/5,36/5)
:::>distance=root((x+4)^2+(3x-7)^2)=root (41)
squaring both sides
:::>10x^2-34x+65=41
:::>10x^2-34x+24=0 ||||| on solving we get x=1,(12/5)
:::>for x=1 y=3
and for x=12/5 , y=36/5
thus the solutions are (1,3) and (12/5,36/5)
Answered by
2
Step-by-step explanation:
hope it helps you....all the best for 2020-20 session of all class students
Attachments:
Similar questions