Physics, asked by adityagopal2005, 6 months ago

Distance between an object and its twice enlarged real image formed by a convex lens is 60 cm. Find object distance , image distance and focal length of the lens. Draw the ray diagram too. Please please please

Answers

Answered by RajatPanwar706
5

Given distance between object and image is 0.72 m

Given distance between object and image is 0.72 mHence, ∣u∣+∣v∣=0.72...........(i)

Given distance between object and image is 0.72 mHence, ∣u∣+∣v∣=0.72...........(i)Also, given magnitude of magnification is 2

Given distance between object and image is 0.72 mHence, ∣u∣+∣v∣=0.72...........(i)Also, given magnitude of magnification is 2∴∣m∣=

Given distance between object and image is 0.72 mHence, ∣u∣+∣v∣=0.72...........(i)Also, given magnitude of magnification is 2∴∣m∣= ∣u∣

Given distance between object and image is 0.72 mHence, ∣u∣+∣v∣=0.72...........(i)Also, given magnitude of magnification is 2∴∣m∣= ∣u∣∣v∣

Given distance between object and image is 0.72 mHence, ∣u∣+∣v∣=0.72...........(i)Also, given magnitude of magnification is 2∴∣m∣= ∣u∣∣v∣

Given distance between object and image is 0.72 mHence, ∣u∣+∣v∣=0.72...........(i)Also, given magnitude of magnification is 2∴∣m∣= ∣u∣∣v∣ =2...........(ii)

Given distance between object and image is 0.72 mHence, ∣u∣+∣v∣=0.72...........(i)Also, given magnitude of magnification is 2∴∣m∣= ∣u∣∣v∣ =2...........(ii)Solving (i) & (ii), we get

Given distance between object and image is 0.72 mHence, ∣u∣+∣v∣=0.72...........(i)Also, given magnitude of magnification is 2∴∣m∣= ∣u∣∣v∣ =2...........(ii)Solving (i) & (ii), we get∣u∣=0.24,∣v∣=0.48

Given distance between object and image is 0.72 mHence, ∣u∣+∣v∣=0.72...........(i)Also, given magnitude of magnification is 2∴∣m∣= ∣u∣∣v∣ =2...........(ii)Solving (i) & (ii), we get∣u∣=0.24,∣v∣=0.48As image is real, u=−0.24,v=0.48

Given distance between object and image is 0.72 mHence, ∣u∣+∣v∣=0.72...........(i)Also, given magnitude of magnification is 2∴∣m∣= ∣u∣∣v∣ =2...........(ii)Solving (i) & (ii), we get∣u∣=0.24,∣v∣=0.48As image is real, u=−0.24,v=0.48Using lens formul

ure answer is .0.1/0.4

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