Distance between an object and the screen is D. Real images of an object are formed on the
screen for two positions of a lens separated by a distance d. The ratio between the sizes of
two images will be
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Answer:The correct option is D) [(D – d)2 / (D + d)2]
Explanation: d(object and screen) = D = u + v and d = v – u Thus d + D = 2v ∴ v = [(d + D) / 2] and u = [(D – d) / 2] ∴ m1 = (I1 / O) = (v/u) = [{D + (d/2)} / {D – (d/2)}] = [(D + d) / (D – d)] m2 = (I2 / O) = (u/v) = [{D – (d/2)} / {D + (d/2)}] = [(D – d) / (D + d)] ∴ (I1 / I2) = [(D + d)2 / (D – d)2]
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