distance between frog and insect on a horizontal plane is 10m. Frog can jump with a maximum speed of root10m+s.minimum no. of jumps required by frog to catch insect is
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10
Let n number of jumps required by frog to catch the insect
Now motion of frog is like a projectile
and the angle will be 45
Range (R) = u²/ g = (√10)² / 10 = 1 m
Now motion of frog is like a projectile
and the angle will be 45
Range (R) = u²/ g = (√10)² / 10 = 1 m
Answered by
7
Answer:
10 Jumps
Explanation:
Formulae of Range=u²sin2∅
g
u=√10m/s
g=10m/s²
r=10m
Here ∅=45⁰(because maximum range)
Therefore,
R=(√10m/s)²*1 (sin2∅=sin90⁰=1)
10m/s²
R=1m
To cover 10m the Frog have to take 10 Jumps to reach insect.
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Thank you for reading.
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