Question

In a Bohr's model of atom when an electron jumps from n=1 to n=3, how much energy will be emitted or absorbed?

a) 2.15*10-11 erg

b) 0.1911*10-10 erg

c) 2.389*10 -12 erg

d) 0.239*10-10 erg

Answer 1

Answer: b) $0.1911\times 10^{-10}erg$

Explanation:

$E=hc\times R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )$

Where,

E= energy =?

h= planck's constant $= 6.6\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

$R_H$ = Rydberg's Constant =$1.09737\times 10^7m^{-1}$

$n_f$ = Higher energy level = 3

$n_i$ = Lower energy level = 1

Putting the values, in above equation, we get

$E=6.6\times 10^{-34}Js\times 3\times 10^8m/s\times 1.09737\times 10^7m^{-1}\left(\frac{1}{1^2}-\frac{1}{3^2} \right)$

$E=0.1911\times 10^{-17}J$        ($1Joule=10^7erg$)

$E=0.1911\times 10^{-10}erg$

Answer 2

Answer:

answer is 4th option hope it helps