Question

Distance between kolkata and Mumbai is 2400 km. Due to some technical problems, the take off of the flight was delayed by 36 mins at Kolkata airport. But to reach in time, the pilot increased the speed by 200 km/hr. What is the usual speed of the flight?

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Answer 1

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Answer 2

Answer:

800 km/hr

Step-by-step explanation:

Distance = 2400 km .

Let usual speed be x .

Speed increased by 200 km/hr

So speed becomes x + 200 .

Time delay is given 36 min .

Time = distance / speed .

So :

2400 / x - 2400 / ( x + 200 ) = 36/60

= > 2400 ( 1/x - 1/( x + 200 ) ) = 3/5

= > 2400 ( x + 200 - x ) / ( x + 200 ) x = 3/5

= > 2400 × 200 / ( x² + 200 x ) = 3/5

= > 480000 × 5 = 3 x² + 600 x

= > 3 x² + 600 x - 2400000 = 0

= > x² + 200 x - 800000 = 0

= > x² + 1000 x - 800 x - 80,000 = 0

= > x ( x + 1000 ) - 800 ( x + 1000 ) = 0

= > ( x - 800 )( x + 1000 ) = 0

x = 800 km/hr neglecting the negative value.