Question

what sum of money is to be deposited at 12% simple interest, to get an amount of rupees. 672 at the end of 1st year?

Answer 1

Answer:

600

Step-by-step explanation:

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Answer 2

$p + pnr = 672 \\ p + p \times 1 \times \frac{12}{100} = 672$

$p + \frac{12p}{100} = 672 \\ \frac{100p + 12p}{100} = 672$

$112p = 672 \times 100 \\ p = \frac{672 \times 100}{112} = 6 \times 100 = rs.600$