Question

distance between point a and b having coordinates (1, 3,4) and(2, 4,6) give answer in explanation form​

Answer 1

Answer:

$\displaystyle \sf \longrightarrow AB = \sqrt{6} \ units$

Explanation:

Given :

Two points A ( 1 , 3 , 4 ) and B ( 2 , 4 , 6 )

We are asked to find distance of AB :

We have distance formula :

$\displaystyle \sf AB = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Putting values we get :

$\displaystyle \sf AB = \sqrt{(2-1)^2+(4-3)^2+(6-4)^2}$

$\displaystyle \sf AB = \sqrt{(1)^2+(1)^2+(2)^2}$

$\displaystyle \sf AB = \sqrt{1+1+4}$

$\displaystyle \sf AB = \sqrt{6} \ units$

Hence we get required answer!