Question

distance between the parallel sides of trapezium which are in the ratio 3 : 5 is 22 CM .If the area of the trapezium is 1100 metre square find the parallel sides of a trapezium​

Answer 1

$ar(tripazium) \: = sum \: of \: parllel \: sides \: \times distence \: between \: them$
put values
$= (3x + 5x) \times 22 = 1100 \\ = 8x \times 22 = 1100 \\ = 176x = 1100 \\ x = \frac{1100}{176} \\ x = 6.25$
then,
$3x = 3 \times 6.25 = 18.75 \\ 5x = 5 \times 6.25 = 31.25$
mark as brainiest answer.

Answer 2

3x + 5x = 22 cm

8x= 22cm

x=22/8

x= 11/4

3x= 11/4*3

=8.25

5x=11/4*5

= 13.75

the answer multiply the answer multiply the answer and the answer which will come divide it that should be equal to 1100