illustrate markovnikovs rule by taking the example of propene?
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we also think that the product will be Ch3-ch3-ch2-br which is 1 bromopropane.but it is not the actual product because negative part of the reagent will go to the carbon having least hydrogen atoms.therefore,2 bromopropane is the actual product.
i really hope that you will find it helpful.stay blessed☺
we also think that the product will be Ch3-ch3-ch2-br which is 1 bromopropane.but it is not the actual product because negative part of the reagent will go to the carbon having least hydrogen atoms.therefore,2 bromopropane is the actual product.
i really hope that you will find it helpful.stay blessed☺
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