Question

Distance between two non-intersecting planes P and P2 is 5 units, where is
2x - 3y +62 +26 = 0 and P, is 4x + by + cz+d=0. The point A(-3.0. - 1) lies between the
planes P, and P, then the value of 3b+4c - 5d is equal to
1) 580
2) 120
3) - 18
4)-120​

Answer 1

Answer:

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