Question

Distance between two points (8,-4) and (0, a) is 10. All the values are in the same unit of length. Find the positive value of a.​​

Answer 1

Answer:

a= (-10,2)

Step-by-step explanation:

x1= 8. y1 = (-4). x2 = 0 y2= a. d=10

distance between the two points. =

√(x2-x1)^2 + (y2-y2)

d =. √(0-8)^2 + [a-(-4)]^2

(10)^2 = (-8)^2 + (a+4)^2

100 = 64 + a^2+8a+16

100= 80+ a^2 +8a

20 = a^2 +8a

a^2 +8a- 20 =0

a^2 +10a-2a -20 =0

a(a+10) - 2(a+10) = 0

a= (-10, 2)

HOPE THIS WILL HELP YOU

Answer 2

Answer:

a = 2

Step-by-step explanation:

d = √[(0 - 8)² + (a - (- 4))²] = 10

64 + (a + 4)² = 10²

a² + 8a + 16 + 64 - 100 = 0

a² + 8a - 20 = 0

(a + 10)(a - 2) = 0

$a_{1}$ = - 10

$a_{2}$ = 2