Distance between two stations a and b is 690 km. Two cars start simultaneously from a and b towards each other, and the distance between them after 6 hours is 30 km.If the speed of one car is less than the other by 10km/hr, find other speed of each car
Answers
Answer:
The speed of the two cars each starting simultaneously from a and b is 50km/h and 60km/h.
Explanation:
Step 1 : Let the speed of one car be x then the speed of the other car will be:
= (x - 10) km/h
Step 2 : Calculate the distance traveled by each car in 6 hours.
Distance = Speed × time
The distance by each car is given by:
(x × 6) and (6 × (x - 10))
= 6x and (6x - 60)
Total distance covered = 6x + 6x - 60 = 12x - 60
From the question the total distance covered by the two is :
= 690 - 30 = 660 km
Step 3 : Equate the two totals and get the value of x.
12x - 60 = 660
12x = 660 + 60
12x = 720
x = 720/12
x = 60 km/h
The speed of the other car is :
= 60 - 10 = 50 km/h
answer:-
The speed of the two cars each starting simultaneously from a and b is 50km/hr and 60km/hr.
Explanation :- Let the speed of one car be x
then speed of another car = (x-10) km/hr
Distance= S×T
The distance by one car = x×6
The distance by another car = 6x-60
Total distance covered = 6x+6x-60 = 12x-60
From the question the total distance covered by two is 690-30 = 660km
Now
12x-60= 660
12x = 660+60
12x = 720
x= 720/12
x= 60
So, The speed of one car is 60km/hr.
And the speed of another car is (60-10)km/hr.
= 50km/hr.