Question

Distance of a point (2,5) from the line x+y-3=0 is​

Answer 1

Answer:

Required distance is 2✓2 cm.

Step-by-step explanation:

Ax + By + C = 0.

On comparing given equation of line with above equation.

A=1

B=1

C= -3

The distance of point from a line, 'd' is the length of the perpendicular drawn from given point ( x1,y1) to line.

So, d = |Ax1 + By1 + C| / (A2 + B2)½.

⇔ d = | 1×2 +1×5 -3|/ (1²+1²)^1/2

⇔d = 4/✓2 = 2✓2 cm.

Answer 2

Given point (2,5)
Line. x+y-3=0

For answer click on the picture