Question

distance of a point p (x,y)from the line L is length of perpendicular from point p (x,y)to line L:Ax+ By+C=0​

Answer 1

Answer:

The answer is $\dfrac{|Ax+By+C|}{\sqrt{A^2+B^2}}$

Step-by-step explanation:

Concept :

Perpendicular distance of point $(x_1,y_1)$ from the line $ax+by+c=0$ is given by

                                    $\dfrac{|ax_1+by_1+c|}{\sqrt{a^2+b^2}}$

Therefore distance of point $P(x,y)$ from the line L : $Ax+By+C=0$ is

                                       $=\dfrac{|Ax+By+C|}{\sqrt{A^2+B^2}}$