Question

In the given figure AD and CE are angle bisectors of angle A and angle C respectively meeting at O. If amgle ABC =90° then (i) angle AOC (ii) angle ADC +angle AEC​

Answer 1

Answer:

Step-by-step explanation:

hello,

let the ΔABC with bisectors of ∠A and ∠C meet BC at D and BA at E

the intersection point be O

∠B=90°

let ∠EAD=∠DAC=x

and ∠ECD=∠ECA=y

in ΔABC,

∠A+∠B+∠C=180°

∠A=x+x=2x

∠C=y+y=2y

⇒90°+2x+2y=180°  (angle sum property of triangle)

2(x+y)=90°

x+y=45°

in ΔAOC,

∠OAC+∠OCA+∠AOC=180°     (angle sum property of triangle)

x+y+∠AOC=180°

45°+∠AOC=180°

∠AOC=135°

hope this helps,if u like please mark it as brainliest

pls pls pls