distance of Chord a circle is8 CM length of the chord ABis12.cm find the diameter of the circle
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o is circle centre and d is mid point of ab so ad is 6
and od is 8 given
by p. t.
(AO)2=(AD)2+(OB)2
AND AO IS RADIUS
(AO)2=(6)2+(8)2
= 36+ 64
= 100
ROOT OF (AO)2 IS AO
ROOT OF 100 IS 10 BUT WE ANSWER IN +AND - BUT WE TAKE ONLY + BECAUSE DISTANCE IS ALWAY IN PLUS
AO=10
DIAMETER = 2 RADIUS
= 2× 10
= 20 CM ANSWER
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