Distance Speed Graphs
A man left home at 12:00 noon to go for cycle ride. At 12:45 pm the man stopped for a rest.
a]For how many minutes did he rest?
b]Find his distance from home at 1:30 pm.
Answers
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Answer:
Let half of the distance travelled be d.
Time taken at the speed of 4 km/hr = (d/4)
Time taken at the speed of 5 km/hr = (d/5)
Therefore, total time = (d/4) + (d/5) = 9 hrs.
⇒ (5d + 4d)/20 = 9
⇒ 9d = 180
⇒ d = 20.
Therefore total distance = d x 2 = 40 kms
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