distance travelled by a body falling from rest in the first second and third second in the ratio of
Answers
Answered by
0
Explanation:
Snth = u + 1/2a(2n-1)
u = 0 m/s ( since body is at free fall)
a = 10m/s²
S1 = 0 + 1/2 * 10(2*1-1)
S1 = 5m
S2 = 0 + 1/2 * 10(2*3-1)
S2 = 25 m
Distance traveling by in the boy in first second and third second is 1:5
Similar questions