Physics, asked by hafsasheikh, 1 year ago

distance travelled by a body falling from rest in the first second and third second in the ratio of​

Answers

Answered by manas3379
0

Explanation:

Snth = u + 1/2a(2n-1)

u = 0 m/s ( since body is at free fall)

a = 10m/s²

S1 = 0 + 1/2 * 10(2*1-1)

S1 = 5m

S2 = 0 + 1/2 * 10(2*3-1)

S2 = 25 m

Distance traveling by in the boy in first second and third second is 1:5

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