Question

distance travelled by the spacecraft in the first 10 s after the rocket motors were started, the motors having been in action for only 6.0 s
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Answer 1

Answer:

acceleration= v-u/t

= 120-75/6

=45/6

= 7.5m/s^2.

distance= ut+1/2at^2

= (75×6)+ 1/2× 45/6×6×6

=450+ 135

= 585 km.

Explanation:

because a= v-u/t

and s= it+1/2at^2.

2as=v^2-u^2.

2×75/10×s= 14400-5625

=15s= 8775

= s= 8775÷15

=585km.