distinguish between esterification and saponification reaction with the help of chemical equation for each case
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The equation for saponification reaction is CH3COOC2H5 → (on treatment with sodium hydroxide) C2H5OH + CH3COONa
The equation for saponification reaction is CH3COOC2H5 → (on treatment with sodium hydroxide) C2H5OH + CH3COONa
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Esterification reaction: when ethanoic acid is treated with ethanol in the presence of concentrated sulphuric acid,then a sweet smelling compound is formed called an ester .
CH3COOH+C2H5OH------------(H2SO4) CH3COOC2H5+H2O
Saponification reaction is converse of esterification reaction in the presence of sodium hydroxide, then we will get back ethanoic acid and ethanol separately.
CH3COOC2H5---------(NaOH) CH3COOH+C2H5OH.
Esterification reaction: when ethanoic acid is treated with ethanol in the presence of concentrated sulphuric acid,then a sweet smelling compound is formed called an ester .
CH3COOH+C2H5OH------------(H2SO4) CH3COOC2H5+H2O
Saponification reaction is converse of esterification reaction in the presence of sodium hydroxide, then we will get back ethanoic acid and ethanol separately.
CH3COOC2H5---------(NaOH) CH3COOH+C2H5OH.
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