Distinguish between esterification and saponification reactions of organic compounds
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138
The reaction between alcohols and carboxylic acids to form esters is called esterification. Mainly can be considered as the reaction in which ester is formed is called esterification.
when this ester reacts with a base(say NaOH) it forms C2H5OH and sodium salt of carboxylic acid which is called saponification.
CH3COOC2H5+NaOH->C2H5OH+CH3COONa(sodium salt of carboxylic acid)
when this ester reacts with a base(say NaOH) it forms C2H5OH and sodium salt of carboxylic acid which is called saponification.
CH3COOC2H5+NaOH->C2H5OH+CH3COONa(sodium salt of carboxylic acid)
Answered by
40
Esterification:
CH3COOH+C2H5OH ==> CH3COOC2H5 + H2O
ESTER IS FORMED AS PRODUCT.
Saponification:
CH3COOH + NaOH ==> CH3COONa + H2O
SODIUM ETHONATE (soap) IS FORMED AS A PRODUCT.
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