Distributing the brithday cake among Reena, Teena and Meena; 2/5 part and Teena given 1/3 part and remaining part was given to Merna. Find the Meena's share.
Answers
Meena's part is y = 4x/5
Step-by-step explanation:
We are given:
- Teena's part = 1/3
- Reean part = 2/5
To find Meena's part = ?
Solution:
Reena part + Teena part + Meena part = x
2x / 5 + x/3 + y = x
y = x - x/3 - 2x/5
y = 15x - 5x -6x /15
y = 15x - 11x / 15
y = 4x / 15
Hence Meena's part is y = 4x/5
Also learn more
Rs 48000 is distributed among a,b and c in the ratio 6:5:4 . What is the difference in the share of a and c?
https://brainly.in/question/6197212
Answer:
Meena's part is y = 4x/5
Step-by-step explanation:
We are given:
Teena's part = 1/3
Reean part = 2/5
To find Meena's part = ?
Solution:
Reena part + Teena part + Meena part = x
2x / 5 + x/3 + y = x
y = x - x/3 - 2x/5
y = 15x - 5x -6x /15
y = 15x - 11x / 15
y = 4x / 15
Hence Meena's part is y = 4x/5
Also learn more
Rs 48000 is distributed among a,b and c in the ratio 6:5:4 . What is the difference in the share of a and c?
Step-by-step explanation:
Hope this answer will help you.✌️