Chemistry, asked by mihirmandavia, 9 months ago

distribution of electrons in oxygen

Answers

Answered by kamleshgarg
1

Answer:

2,6

Explanation:

Since the atomic number of oxygen is 8

therefore, according to the 2n^2 rule the electronic configuration will be 2, 6

i.e. 2 electrons in the K- shell and 6 electrons in the L- shell( here, valence shell)

I hope it helps .

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