Math, asked by armaanian, 1 year ago

DIVIDE :--
1) -x⁶ + 2x⁴ + 4x³ + 2x² by √2 x²
2) √3 a⁴ + 2√3 a³ + 3a² - 6a by 3a

Answers

Answered by Anonymous
6
DIVISION ALGORITHMS IMPLIED
Attachments:

armaanian: thnx
Anonymous: YOU'RE ALWAYS WELCOME
Anonymous: :)
armaanian: i will just blindly copy ... cz question samjah hi nhi aarha
Anonymous: Yeah surely
Answered by Anonymous
8
Hello Dear :)
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1)
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 \frac{-x^6 + 2x^4 + 4x^3+2x^2  }{ \sqrt{2x^2} }

 \frac{x^2(-x^4+2x^2+4x+2)}{ \sqrt{2}x^2 }

 \frac{-x^4+2x62+4x+2}{ \sqrt{2} }

 \frac{-x^4}{ \sqrt{2} } + \frac{2x^2}{ \sqrt{2} } +  \frac{4x}{ \sqrt{2} } + \frac{2}{ \sqrt{2} }

 \frac{-x^4}{ \sqrt{2} } + \sqrt{2} x^2 + 2 \sqrt{2} x + \sqrt{2}

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2)
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 \frac{ \sqrt{3}a^4 +2 \sqrt{3} a^3+3a^2-6a }{3a}

 \frac{ \sqrt{3} a(a^3 + 2a^2 +  \sqrt{3}a-2 \sqrt{3} ) }{ \sqrt{3}  .\sqrt{3} a}

 \frac{a^3 + 2a^2 + \sqrt{3}a-2 \sqrt{3}}{ \sqrt{3} }

 \frac{a^3}{ \sqrt{3} } + \frac{2a^2}{ \sqrt{3} } +a -2
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armaanian: thnx
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