divide 1 + Y to the power 3 by 1 + Y
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(1+Y)^2
hope this helps...
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Answer:
(y+1)(y^2-y.1+1) / (y+1)
= (y^2 -y+1)
using algebraic formula
(a^3 +b^3)= (a+b)(a^2-a.b+b^2)
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