Divide 10y(6y+21)÷5(2y+7)
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Answered by
28
=10y(6y+21)÷5(2y+7)
=2y*3(2y+7)÷(2y+7)
=2y*3
=6y
=2y*3(2y+7)÷(2y+7)
=2y*3
=6y
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angad005:
but how did you divide 12y^2 +42y by 2y +7
why nt take 6y common from first n thn 2y+7 is left
can you re answer this question with a photo
i hv send
oh thanks now I understand
Thanks
Answered by
11
ITS VERY EASY
10Y(6Y+21) / 5(2Y+7)
60Y²+210Y = 5(2Y+7)
60Y²+210Y = 10Y + 35
60Y²+210Y-10Y-35 = 0
60Y²+200Y-35 = 0
5[12Y²+40Y-7] = 0
12Y²+40Y-7 = 0/5
12Y²+42Y-2Y-7 = 0
6Y[2Y+7]-1[2Y+7] = 0
[2Y+7] [6Y-1] = 0
Y = -7/2 ; 1/6
HOPE YOU UNDERSTAND
its very wrong answer
SRY I THINK VALUE OF Y IS FIND OUT
it's ok
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