evaluate 6t-20-32u when t=6 and u=1/5
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it is given that 6t-20-32u where
t=6 and u=1\5
so substitute
6(6)-20-32(1/5)
=36-20-32/5
=16-32/5
=9.6
t=6 and u=1\5
so substitute
6(6)-20-32(1/5)
=36-20-32/5
=16-32/5
=9.6
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